.png) |
Solution of the problem of Apollonius with imaginary elements |
|
| |
Back to the task list |
| |
The information presented in this lesson task is implemented in a software system Simplex |
| |
|
| 1 |
Now we solve the problem of Apollonius to construct a circle tangent to three given, based on the concept of an orthogonal imaginary circle, discussed in the previous lesson.
Start a new project.
Let three circles sre given the plane, which are clearly disjoint.

Fig. 1 |
| |
|
| 2 |
Construct tangents o1 and o2 to circles d1 and d3.

Fig. 2 |
| |
|
| 3 |
Find the intersection point p5 of the tangents o1 and o2.

Fig. 3 |
| |
|
| 4 |
Construct the intersection point p10 tangent to circles d2 and d3.

Fig. 4 |
| |
|
| 5 |
Construct the intersection point p15 tangent to circles d1 and d3.

Fig. 5 |
| |
|
| 6 |
Draw a straight line o7 passing through the three points p5, p10 and p15. To do this, select the point and press the button with the Latin symbol q.

Fig. 6 |
| |
|
| 7 |
Find the radical center of three circles - point p16.

Fig. 7 |
| |
|
| 8 |
Determine the center of the original circle - points p17, p18, p19.

Fig. 8 |
| |
|
| 9 |
Construct triangle with sides o10, o11, o12 based on points p17, p18, p19

Fig. 9 |
| |
|
| 10 |
Map the radical center p16 in the inversion circles d1, d2 and d3. We get the points p20, p21, p22.

Fig. 10 |
| |
|
| 11 |
Draw circles d4, d5, d6 passing trough the radical center and all possible pairs of a triad of points p20, p21, p22 .

Fig. 11 |
| |
|
| 12 |
Find the points p23 and p24 of intersection of the line o12 and d5 circle.

Fig. 12 |
| |
|
| 13 |
Calculate the radius of the imaginary circle orthogonal finding the distance c1 between the radical center point p16 and the point p24.

Fig. 13 |
| |
|
| 14 |
Define an imaginary circle d7 with real center of p16 and the value c1.

Fig. 14 |
| |
|
| 15 |
Points p25 and p26 are the intersection of circles d7 and d1.

Fig. 15 |
| |
|
| 16 |
Draw a straight line o13 passing through the points p25 and p26.

Fig. 16 |
| |
|
| 17 |
Points p27 and p28 are the intersection of circles d7 and d2.

Fig. 17 |
| |
|
| 18 |
Draw a straight line o14 passing through the points p27 and p28.

Fig. 18 |
| |
|
| 19 |
Points p29 and p30 are the intersection of circles and d7 d3.

Fig. 19 |
| |
|
| 20 |
Draw a straight line o15 passing through the points p29 and p30.

Fig. 20 |
| |
|
| 21 |
Construct a circle d8, passing perpendicular to the lines o13, o7 and circle d1.

Fig. 21 |
| |
|
| 22 |
Find the intersection points p31, p32 of circles d8 and d1.

Fig. 22 |
| |
|
| 23 |
Construct a circle d9, passing perpendicular to the lines o15, o7, and circle d3 .

Fig. 23 |
| |
|
| 24 |
Find the intersection points p33, p34 of circles d3 and d9.

Fig. 24 |
| |
|
| 25 |
Construct a circle d10, passing perpendicular to the line o14, o7 and circle d2.

Fig. 25 |
| |
|
| 26 |
Find the intersection points p35, p36 of circles d10 and d2.

Fig. 26 |
| |
|
| 27 |
Draw a circle d10, passing orthogonal to the lines o7, o14 and circle d2.

Fig. 27 |
| |
|
| 28 |
Draw the desired d11 circle passing through the points p32, p34, p35 and d12 passing through the points p31, p36 and p33.

Fig. 28 |
| |
|
| 29 |
 |
| |
|
| 30 |
 |
| |
|
| 31 |
 |
| |
|
| 32 |
 |
| |
|
| 33 |
 |
| |
|
| 34 |
 |
| |
|
| 35 |
 |
| |
|
| 36 |
 |
| |
|
| 37 |
 |
| |
|
| 38 |
 |
| |
|
| 39 |
 |
| |
|
| 40 |
 |
| |
|
| 41 |
 |
| |
|
| 42 |
 |
| |
|
| 43 |
 |
| |
|
| 44 |
 |
| |
|
| 45 |
 |
| |
|
| 46 |
 |
| |
|
| 47 |
 |
| |
|
| 48 |
 |
| |
|
| 49 |
 |
| |
|
| 50 |
 |
| |
|
| 51 |
 |
| |
|
| |
 |